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in Continuity and Differentiability by (46.3k points)

Examine the function for differentiability at x = a if f(x) = \(\begin{cases} (x - a)^2sin(\frac{1}{x - a}); &x \neq a\\ 0;& x = a \end{cases} \)

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Hence, function is differentiable at x = 0.

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