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If f(x) = \(\begin{cases} x - 1; & x < 2\\ 2x - 3;& x \geq2 \end{cases}\)

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If f(x) = \(\begin{cases} x - 1; & x < 2\\ 2x - 3;& x \geq2 \end{cases} \)  then find f'(2 - 0).

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Hence, f'(2 - 0) = 1

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