(a) \(\int\frac{sin(x - a)}{sin(x + a)}dx\)
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= cos 2a ∫ dt – sin 2a ∫ cot t dt
= (cos 2a)t – sin 2a log | sin t | + C1
= (x + a) cos 2a – sin 2a log | sin (x + a) | + C1
= x cos 2a – sin 2a log | sin (x + a) | + a cos 2a + C1
= x cos 2a – sin 2a log | sin (x + a) | + C
( where C = a cos 2a + C1)
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![](https://www.sarthaks.com/?qa=blob&qa_blobid=1166410252427005913)