Question

Integrate the following :

(a) \(\int e^x(\frac{1 - sinx}{1 - cosx})dx\)

(b) \(\int e^x [loga + \frac{1}{x^2}]dx\)

Answer 1

(a) \(\int e^x(\frac{1 - sinx}{1 - cosx})dx\)

(b) \(\int e^x [loga + \frac{1}{x^2}]dx\)

Answer 2

(A) This is the first answer

(B)