Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
1.4k views
in Mathematics by (10.7k points)
12x^2 - 7x + 1 using factor theorem; not by middle term splitting

2 Answers

+2 votes
by (58.8k points)
selected by
 
Best answer

Consider the polynomial function f(x) = 12x2 - 7x + 1

The values of x for which f(x)=0 are called the roots of the function. By solving the equation, f(x)=0

Then, we get

12x2 - 7x + 1

12x− 4x − 3x + 1 

= 4x(3x−1)−1(3x−1) 

=(4x−1)(3x−1)

(4x-1) = 0 or (3x-1) = 0

4x = 1 or 3x = 1

x = 1/4 or x = 1/3

Because (4x - 1) and (3x - 1) is a factor of 12x2 - 7x + 1 , 1/4 and 1/3 are the solutions to the equation 12x2 - 7x + 1 = 0, we can also check as follows:

If x = 1/4 is the solution , then

f(x)= 12x2 - 7x + 1

f(1/4) = 12(1/4)2 - 7(1/4) + 1

f(1/4) = 12 x 1/16 - 7/4 + 1

f(1/4) = 12/16 - 7/4 + 1

f(1/4) = (28-28)/16

f(1/4)=  0

If x = 1/3 is the solution, then;

f(x)= 12x2 - 7x + 1

f(1/3)= 12 (1/3)2 - 7(1/3) + 1

f(1/3) = 12 x 1/9 - 7/3 + 1

f(1/3) = 12/9 -7/3 + 1

f(1/3) = (21-21)/9

f(1/3)= 0

If the remainder is zero, (x-c) is a polynomial of f(x).

–1 vote
by (63.2k points)

12x2−7x+1

=12x2−4x−3x+1

=4x(3x−1)−1(3x−1)

=(4x−1)(3x−1)

by (10.7k points)
This is not factor theorem. You have solved this question using Middle Term splitting.

No related questions found

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...