Consider the polynomial function f(x) = 12x2 - 7x + 1
The values of x for which f(x)=0 are called the roots of the function. By solving the equation, f(x)=0
Then, we get
12x2 - 7x + 1
12x2 − 4x − 3x + 1
= 4x(3x−1)−1(3x−1)
=(4x−1)(3x−1)
(4x-1) = 0 or (3x-1) = 0
4x = 1 or 3x = 1
x = 1/4 or x = 1/3
Because (4x - 1) and (3x - 1) is a factor of 12x2 - 7x + 1 , 1/4 and 1/3 are the solutions to the equation 12x2 - 7x + 1 = 0, we can also check as follows:
If x = 1/4 is the solution , then
f(x)= 12x2 - 7x + 1
f(1/4) = 12(1/4)2 - 7(1/4) + 1
f(1/4) = 12 x 1/16 - 7/4 + 1
f(1/4) = 12/16 - 7/4 + 1
f(1/4) = (28-28)/16
f(1/4)= 0
If x = 1/3 is the solution, then;
f(x)= 12x2 - 7x + 1
f(1/3)= 12 (1/3)2 - 7(1/3) + 1
f(1/3) = 12 x 1/9 - 7/3 + 1
f(1/3) = 12/9 -7/3 + 1
f(1/3) = (21-21)/9
f(1/3)= 0
If the remainder is zero, (x-c) is a polynomial of f(x).