It is given that length = 15m, breadth = 6m and height = 5dm = 0.5m
We know that
Volume of cuboid = l × b × h
By substituting the values we get
Volume of cuboid = 15 × 6 × 0.5
By multiplication
Volume of cuboid = 45 m3
We know that
Lateral surface area of a cuboid = 2 (l + b) × h
By substituting the values
Lateral surface area of a cuboid = 2 (15 + 6) × 0.5
On further calculation
Lateral surface area of a cuboid = 2 × 21 × 0.5
By multiplication
Lateral surface area of a cuboid = 21 m2
We know that
Total surface area of cuboid = 2 (lb + bh + lh)
By substituting the values
Total surface area of cuboid = 2 (15 × 6 + 6 × 0.5 + 15 × 0.5)
On further calculation
Total surface area of cuboid = 2 (90 + 3 + 7.5)
So we get
Total surface area of cuboid = 2 × 100.5
By multiplication
Total surface area of cuboid = 201 m2