It is given that
Diameter of the conical heap = 9m
Radius of the conical heap = 9/2 = 4.5m
Height of the conical heap = 3.5m
We know that
Volume of the conical heap = 1/3 πr2h
By substituting the values
Volume of the conical heap = 1/3 × 3.14 × 4.52 × 3.5
On further calculation
Volume of the conical heap = 3.14 × 1.5 × 4.5 × 3.5
So we get
Volume of the conical heap = 74.1825 m3
We know that
Slant height l =√ (r2 + h2)
By substituting the values
l = √ (4.52 + 3.52)
On further calculation
l = √ 32.5
So we get
l = 5.7 m
We know that
Curved surface area of the conical heap = πrl
By substituting the values
Curved surface area of the conical heap = 3.14 × 4.5 × 5.7
On further calculation
Curved surface area of the conical heap = 80.54 m2
Therefore, 80.54 m2 of canvas is required to cover the heap of wheat.