It is given that
Diameter of the sphere = 6cm
Radius of the sphere = 6/2 = 3cm
Diameter of the wire = 2mm = 0.2 cm
Radius of the wire = 2/2 = 1mm = 0.1 cm
Consider h cm as the required length
So we get
πr2h = 4/3 πR3
By substituting the values
(22/7) × 0.12 × h = 4/3 × (22/7) × 33
On further calculation
h = (4/3 × (22/7) × 27)/ ((22/7) × 0.12)
So we get
h = 36/0.01 = 3600cm = 36m
Therefore, the length of the wire is 36m.