Consider △ AFE and △ DFE
Using the midpoint theorem
AF = ½ AB = ED
AE = ½ AC = FD
FE is common i.e. FE = EF
By SSS congruence criterion
△ AFE ≅ △ DFE
∠ A = ∠ FDE (c. p. c. t)
In the same way we get ∠ B = ∠ DEF and ∠ C= ∠ DFE.
Therefore, it is proved that ∠ EDF = ∠ A, ∠ DEF = ∠ B and ∠ DFE = ∠ C.