(i) We know that OB = OC which is the radius
The base angles of an isosceles triangle are equal
So we get
∠OBC = ∠OCB = 55o
In △ BOC
Using the angle sum property
∠BOC + ∠OCB + ∠OBC = 180o
By substituting the values
∠BOC + 55o + 55o = 180o
On further calculation
∠BOC = 180o – 55o – 55o
By subtraction
∠BOC = 180o – 110o
So we get
∠BOC = 70o
(ii) We know that OA = OB which is the radius
The base angles of an isosceles triangle are equal
So we get
∠OBA= ∠OAB = 20o
In △ AOB
Using the angle sum property
∠AOB + ∠OAB + ∠OBA = 180o
By substituting the values
∠AOB + 20o + 20o = 180o
On further calculation
∠AOB = 180o – 20o – 20o
By subtraction
∠AOB = 180o – 40o
So we get
∠AOB = 140o
We know that
∠AOC = ∠AOB – ∠BOC
By substituting the values
∠AOC = 140o – 70o
So we get
∠AOC = 70o