It is given that BC = 5cm, ∠B = 80o, ∠C = 50o and ∠A = 60o
The sum of any two sides of a triangle is greater than the third side
It can be written as
∠A + ∠B + ∠C = 60o + 80o + 50o
So we get
∠A + ∠B + ∠C = 190o > 180o
Therefore, construction of △ ABC for the measurements given is not possible.