Given 20 is the smallest number in Pythagorean triplet But we have for every number m>1, we have (2m, m2-1, m2+1) as a Pythagorean triplet Using the above condition we can write as 2m = 20
m= 20/2=10
Then m2 =100
m2 – 1 = 100 – 1 = 99
m2 + 1 = 100 + 1 =101
Therefore the Pythagorean triplet is = (2m, m2-1, m2+1) = (20, 99, 101)
