Firstly we have to find the factors for the above numbers
∛141 = \(\sqrt[3]{(3 × 47)}\)
∛294 = \(\sqrt[3]{(2 × 3 × 7 × 7)}\)
∛216 = \(\sqrt[3]{(6 × 6 × 6)}\)
∛496 = \(\sqrt[3]{(2 × 2 × 2 × 2 × 31)}\)
From the above results, 216 has the perfect cube factors.
∴ 216 is the perfect cube.
