Question

The constant term in the expansion (2x + 1/3x²)⁹

(A) 5^th

(B) 4^th

(C) 6^th

(D) 7^th

Answer 1

Answer is (B) 4^th

(r + 1)^th term in the expansion of

For constant term

x⁹ – 3r = x⁰

⇒ 9 – 3r = 0

⇒ r = 3

Hence, r + 1 = 3 + 1 = 4^th term is the constant term