Question

Find the value of x from following equation
log_x4 + log_x16 + log_x64 = 12

Answer 1

log_x 4 + log_x 16 + log_x 64 = 12

⇒ log_x 4 + log_x 42 + log, 43 = 12

⇒ log_x 4 + 2 log_x 4 + 3 log_x 4=12

⇒ 6 log_x 4 = 12

⇒ log_x 4 = 2

⇒ log_x 2^x = 2

⇒ 2 log_x 2 = 2

⇒ log_x 2 = 1

⇒ log_x 2 = log₂ 2

On comparing, x = 2