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If vector a = 2i + 2j + 3k, vector b = -i + 2j + k and vector c = 3i + j

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If vector a = 2i + 2j + 3k, vector b = -i + 2j + k and vector c = 3i + j are such that vector a + λ vector b is perpendicular to vector c, then find the λ.
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(6 + 2) + λ(–3 + 2) = 0

λ = 8

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