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in Logarithms by (46.3k points)

(a) If antilog 1.5662 = 36.83, then find the value of the following :

(i) antilog \(\bar{1}\).5662

(ii) antilog 2.5662

(iii) antilog \(\bar{2}\).5662

(b) Find the value of antilog (log x).

1 Answer

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(a) Given, antilog 1.5662 = 36.83

(i) ∵ Mantissa of 1.5662 and 1.5662 are same. 

So, anitlog of two number will be same digit numbers.

Now, characteristics of which number is 1 then there will be no zero after decimal point in antilog.

∴ Required antilog \(\bar{1}\).5662 = 0.3683.

(ii) ∵ Mantissas of 1.5662 and 2.5662 are same.

So, antilog of two numbers will be same digit number.

Now, characteristic of which number is 2 then decimal point will be after 3 digit in antilog.

∴ Required anitlog 2.5662 = 368.3.

(iii) ∵ Mantìssa of 1.5662 and \(\bar{2}\).5662 are same.

So. antilog of two numbers will be same digit number.

Now, characteristic of which number is \(\bar{2}\) then there will be one zero after decimal point in anitlog.

∴ Required antilog \(\bar{2}\).5662 = 0.03683.

(b) antilog and log are opposite to each other.

∴ antilog (log x) x.

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