Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
4.1k views
in Constructions by (51.6k points)

Construct a parallelogram ABCD in which AB=4.3cm, AD=4cm and BD=6.8cm

1 Answer

+1 vote
by (49.9k points)
selected by
 
Best answer

The given Parallelogram ABCD can be drawn by following the steps.

Step1: Draw a line AB= 4.3cm

Step2: Draw an arc of 6.8cm from B

Step3: From A take radius of 4cm and cut the arc drawn in step2 and that point of intersection is D. join AD and BD.

Step4: Draw another arc from B with 4cm as radius.

Step5: From A take 6.8cm and cut the arc drawn in step4 and the point of intersection is C. now join BC and AC.

∴ The constructed parallelogram looks like:

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...