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in Measures of Dispersion by (48.0k points)
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Find the mean and standard deviation of the following frequency distribution by step deviation method.

Class 1-5 6-10 11-15 16-20 21-25 26-30 31-35
Frequency 5 7 18 25 20 4 1

1 Answer

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Best answer

Mean (\(\bar{x}\)) = 1/N∑f1x1 = 1/80 x 1360 = 17

Standard deviation (σ) = √(1/N∑f1(x1 - \(\bar{x}\))2

= √(1/80 x 3320) = √(41.5) = 6.44

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