Question

A particle is dropped from a 200 m tall tower. At the same time a second particle is thrown upwards with velocity 50 m/s. Calculate when and where would these two particles (bodies) meet.

Answer 1

Suppose both the bodies y meet at point C. Now, the distance h travelled by the body A which is dropped freely from the top of the tower, using relation,

∴ The height of meeting point of both the bodies from the ground.
= 200 – h = 200 - 78.4 = 121.6 m
Thus both the bodies will meet after 4s at the height of 121.6 m from the ground.