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If A = 60° and B = 30° then prove that : cot (A – B) = (cotAcotB + 1)/(cotB - cotA)

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If A = 60° and B = 30° then prove that : cot (A – B) = (cotAcotB + 1)/(cotB - cotA)

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cot (A – B) = (cotAcotB + 1)/(cotB - cotA)

∴ A = 60°, B = 30°

L.H.S. = cot(A-B) = cot(60° – 30°)

= cot 30° = √3

RHS = (cotAcotB + 1)/(cotB - cotA)

L.H.S. = R.H.S.

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