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The angle of elevation of the top of a tower from a point situated at 100 m far from the foot of tower is 300.

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The angle of elevation of the top of a tower from a point situated at 100 m far from the foot of tower is 300. Find the height of the tower.

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Let height of tower BC = h meter and angle of elevation is 30° from point A which is 100 m from the base B of tower then

∠BAC = 30°

From right angled ∆ABC,

Hence, height of the tower 57.73 m

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