Question

The horizontal distance between two towers is 140 m. The angle of elevation of the top of first tower when seen from the top of second tower is 30°. If the height of the second tower is 60 m then find the height of first tower.

Answer 1

Let AB is a tower of height h and other tower is ED of height 60 m.

Distance between two towers EB = DC = 140 m

The angle of elevation of the top of first tower when seen from the top of second tower is 30°.

So, ∠ADC = 30°.

From right angled ∆ACD,

Hence, height of first tower = 140.8 m.