Question

A shearing force of 9.0 × 10⁴ N is applied on a thin surface of a square glass slab of 50 cm side and width 10 cm. Second thin surface is stick to the floor. How much will the upper surface get displaced?

Answer 1

Given, F = 9.0 × 10⁴ N, length of slab = 50 cm = 50 × 10^-2 m
Width of slab = 10cm = 10 × 10^-2 m
∴ Area of slab = 50 × 10^-2 × 10 × 10^-2
= 5 × 10^-2 m²
Modulus of rigidity of glass = 5.6 × 10⁹ Nm^-2