(i) One-one but not onto
Consider A = {1, 2, 3} and B = {a, b, c, d}
So we get f = {(1, a), (2, b), (3, c}

(ii) One-one and onto
We know that f(x) = 2x
Infectivity:
Consider x1, x2 ∈ R where f(x1) = f(x2)
So we get
2x1 = 2x2
x1 = x2
Hence, f: R → R is one-one
Subjectivity:
Consider y be any real number in R which is the co-domain
f(x) = y
We get
2x = y
It can be written as
x = y/2
We know that y/2 ∈ R for y ∈ R where
f(y/2) = 2(y/2) = y
For y ∈ R(co-domain) there exists x = y/2 ∈ R (domain) where f(x) = y
Here, each element in co-domain has pre-image in domain
Thus, f: R → R is bijective.
(iii) Neither one-one nor onto
Consider A = {1, 2, 3} and B = {4, 5, 6}
We get
f = {(1, 4), (2, 4), (3, 5)}

(iv) Onto but not one-one
Consider A = {1, 2, 3} and B = {4, 5, 6}
We get
f = {(1, 2), (3, 2), (5, 4)}
