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A man slides down a light rope the breaking strength of which is β times his weight (β < 1).

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A man slides down a light rope the breaking strength of which is β times his weight (β < 1). The maximum acceleration of man so that the rope just breaks is

(A) βg

(B) (1 - β)g

(C) g/(1 + β)

(D) g/(2 + β)

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(B) The maximum acceleration of man so that the rope just breaks is (1 - β)g.

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