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In ∆ABC if AD of is bisector of ∠A and AB = 8 cm, BD = 5 cm and DC = 4 cm. then find AC.

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In ∆ABC

AD, bisect vertex angle A

∴ ∠BAD = ∠CAD

∴ AB/AC = BD/DC

⇒ 8/AC = 5/4

⇒ 5 AC = 8 × 4

⇒ AC = 32/5

⇒ AC = 6.4 cm

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