Question

AB and AC arc two chords of a circle of radius r such that AB = 2 AC. If P and Q are respectively distance from center to AB and AC then Prove that 4q² = p² + 3r²

Answer 1

Given : From the center O of circle with center r, p and q arc respectively distance to AB and AC such that AB = 2 AC

To Prove : 4q² = p² + 3r²

Construction : Drew perpendicular from center O to chords AB and AC which cuts chord at M and N respectively.