In ∆ABC in which AB = 5 cm, BC = 6 cm and ∠B = 60°.
To construct: In circle ∆ABC.
Steps of construction:
(1) Draw a line segment BC = 60 cm.
(2) Draw a ray BX making an angle of 60° at B of BC. Cut BA = 5 cm.
(3) Join A to C.
∆ABC is the given triangle.
(4) Draw the bisectors of ∠B and ∠C which intersect each other at O.
(5) Draw OD ⊥ BC from O.
(6) Taking O as center and OD as radius draw a circle which touches three sides of ∆ABC.
This is the required in circle.
