Given the given the segment be AB = 7.8cm.
STEPS : (i) Draw the line segment AB = 7.8cm.
(ii) With point A as centre and a suitable radius, more than half the length of AB, draw arcs on both the sides of AB.
(iii) With point B as centre and with the same radius draw arcs on both the sides of AB. Let these arc cut at points P & Q as shown on in the figure.
(iv) Draw a line through the points P and Q. The line so obtained is the required perpendicular bisector of given line segment AB.
Line PQ is perpendicular bisector of AB.
(A) PQ bisects AB i.e., OA = OB.
(B) PQ is perpendicular to AB i.e., ∠PAO = ∠POB = 90º.
Proof : In ΔAPQ and ΔBPQ
=> PQ is perpendicular bisector of AB.
