Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
5.2k views
in Surface Area and Volume by (35.3k points)
closed by

A solid toy is in the form of a hemisphere surmounted by a right circular cone. If radius of the cone and the total height of the toy are 7 cm and 31 cm respectively. Find the total surface are of the toy. \(\left( Take\; \pi =\frac { 22 }{ 7 } \right) \)

1 Answer

+1 vote
by (34.1k points)
selected by
 
Best answer

Given,

The common radius of conical part and

hemispherical part of the toy (r) = 7 cm.

Total height of the toy = 31 cm

Hence, the height of conical part 

= 31 – 7 = 24 cm

Slant height of conical part l

Total surface area of toy

= Surface of conical part + curved surface area of hemispherical part

Hence, total surface area of toy = 858 cm2

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...