Given,
Diameter of metallic sphere = 8 cm
∴ Radius (R) = \(\frac { 8 }{ 2 }\) = 4 cm
The length of wire recasted (h) = 12 m = 1200 cm
Let the radius of wire recasted be r since, by melting the metallic sphere, the wire is recasted.
∴ Volume of cylindrical wire = Volume of sphere

Hence the thickness of the wire = \(\frac { 8 }{ 15 }\) cm