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AD is the median of any ∆ABC. Is it true to say that AB + BC + CA > 2AD. Give reason for your answer.

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Yes, if AD is median of ∆ABC

⇒ AB + BD > AD …(i) (sum of any two sides of a A is greater than third side)

and AC + DC > AD …(iii) (reason as above)

⇒ AB + (BD + DC) + AC > 2 AD

⇒ AB + BC + CA > 2AD

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