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Construct a triangle PQR when QR = 8 cm, ∠Q = 120° and ∠R = 30°

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Construct a triangle PQR when QR = 8 cm, ∠Q = 120° and ∠R = 30°

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Steps of construction: 

1. Draw line segment QR = 8 cm. 

2. With Q as centre, draw an angle of 120°. 

3. Again with centre, draw an angle of 30° which intersects the arms of angle 120° at P. 

Hence, ∆PQR is the required triangle.

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