Given: ABC is a triangle, in which AB = 3.3 cm,
AC = 2.8 cm and altitude AD = 2.3 cm.
To construct ∆ABC.
Steps of construction:
- Draw a straight line PQ and mark a point D in it.
- Draw DX ⊥ PQ.
- From DX cut off DA = 2.3 cm.
- With A as centre and radii 3.3 cm, 2.8 cm, draw arcs to cut PQ at B, and C respectively.
- Join AB and AC.
Hence, ∆ABC is the required triangle.