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In the given figure, if area of the parallelogram ABCD is 30 cm^2, then ar (∆ADE) + ar (∆BCE) is equal to:

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in Area of Triangles and Quadrilaterals by (34.1k points)

In the given figure, if area of the parallelogram ABCD is 30 cm2, then ar (∆ADE) + ar (∆BCE) is equal to:

(A) 20 cm2

(B) 30 cm2

(C) 15 cm2

(D) 25 cm2

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1 Answer

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by (31.2k points)

Answer is (C) 15 cm2

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