Volume of solid cube of side
12 cm = 12 cm x 12 cm x 12 cm
Number of cubes of equal volume = 8
Volume of one such cube
= \(\frac { 12\times12\times12 }{ 8 }\) cm3 = 216 cm3
Edge of the new cube = 3√216 cm3 = 6 cm
Surface area of one big cube of side/edge 12 cm
= 6 x (12 cm)2 = (6 x 144) cm2
Also surface area of one smaller cube
= 6 x (6 cm)2 = (6 x 36) cm2
Required ratio = \(\frac { 6 \times144 }{ 6 \times 36 }\) = 4 : 1.