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Sum the series to n term:

1 + 3 + 6 + 10 + 15 + …

1 Answer

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Best answer

Let Tn be the nth term and Sn be the sum to n terms of the given series.

We have,

Sn = 1 + 3 + 6 + 10 + 15 + …………. + Tn-1 + Tn … (1)

Equation (1) can be rewritten as:

Sn = 1 + 3 + 6 + 10 + 15 + …………. + Tn-1 + Tn ……..(2)

By subtracting (2) from (1) we get

Sn = 1 + 3 + 6 + 10 + 15 + …………. + Tn-1 + Tn

Sn = 1 + 3 + 6 + 10 + 15 + …………. + Tn-1 + Tn

0 = 1 + [2 + 3 + 4 + 5 + … + (Tn – Tn-1)] – Tn

The difference between the successive terms are 2, 3, 4, 5

So these differences are in A.P

Now,

∴ The sum of the series is n/6 (n + 1) (n + 2)

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