Let a – d, a, a + d be the three angles of the triangle that form AP.
Since greatest angle is double the least. …………… (given)
So, a + d = 2(a – d)
or a + d = 2a – 2d
or a = 3d ……(1)
Again, by angle sum property, we know
Sum of all the angles = 180 degrees
So, (a – d) + a + (a + d) = 180°
or 3a = 180°
or a = 60° …… (2)
From (1) and (2), we get
3d = 60°
or d = 20°
Now, the angles are,
a – d = 60° – 20° = 40°
a = 60°
a + d = 60° + 20° = 80°.
Therefore the required angles are 40°, 60° and 80°.