Question

Reduce the equation of the plane 4x – 3y + 2z = 12 to the intercept form, and hence find the intercepts made by the plane with the coordinate axes.

Answer 1

Equation of the plane is 4x – 3y + 2z = 12

It can be written as

It is the equation of the plane in intercept form

So the x-intercept = 3, y-intercept = – 4 and z-intercept = 6