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Evaluate: ∫(tan x sec^2 x/(1 - tan^2 x)) dx

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Evaluate: ∫(tan x sec2 x/(1 - tan2 x)) dx

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1 Answer

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Best answer

Consider 1 - tan2 x = t

We get

-2 tan x sec2 x dx = dt

By integrating w.r.t t 

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