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A solution containing 0.5 g of KCl dissolves in 100 g of water and freezes at - 0.24°C. Calculate the degree of dissociation of the salt. (Kfor water = 1.86°C), Atomic weights [K = 39, Cl = 35.5]

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w = 0.5 g of KCl

Kf = 1.86°C

W = 100 g of water

m of KCl = K + Cl

= 39 + 35.5 = 74.5 g

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