Question

A square matrix A[m*m] is stored in the memory with each element requiring 2 bytes of storage. If the base address A[1] [1] is 1098 and the address at A [4] [5] is 1144, determine the order of the matrix A[m × m] when the matrix is stored Column Major wise.

Answer 1

B = 1098, W = 2, n = m 

1144 = 1098 + 2 [m(5 – 1) + (4 – 1)] 

⇒ 1144 = 1098 + 8m + 6 

⇒ 8m = 40 

⇒ m = 5 

The order of the matrix is [5 × 5]