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What happens when

  1. Cl2 reacts with hot concentrated solution of NaOH.
  2. XeF6 is mixed with SbF5 and heated.

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  1. Disproportionation reaction takes place in which chlorine from its zero oxidation state in Cl2 gets disproportionate into NaC103 (oxidised form) and NaCl (reduced form). The reaction is
    3Cl2 + 6 NaOH (Hot and cone.) → NaClO3 + 5 NaCl + 3 H2O
  2. XeF6 + SbF5 → [XeF5]+[SbF6]
    XeF6 loses its F ion which is taken by SbF5 to form cationic and anionic species. Due to ionic species, this mixture will conduct electricity in molten state.

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