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Draw graphs of x- 2y = 4, 2x – 4y = 12 on the same co-ordinate plane. Observe it. Think of the relation between the coefficients of x, coefficients of y and the constant terms and draw the inference.

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i    x = 2y = 4 

∴ 2y = x - 4 

∴  y = \(\frac{x-4}{2} \)

x

0

2

-2

4

y

-2

-1

-3

0

(x,y)

(0,-2)

(2,-1)

(-2,-3

(4,0)

 2x - 4y = 12

∴ x - 2y = 6   .........[Dividing both sides by 2]

∴  2y = x - 6

∴   y= \(\frac{y-6}{2} \)

x

0

-2

2

4

y

-3

-4

-2

-1

(x,y)

(0,-3)

(-2,-4)

(2,-2

(4,-1)

ii. Ratio of coefficients of x =\(\frac{1}{2} \)

Ratio of coefficients of y = \(\frac{-2}{-4} \)=\(\frac{1}{2} \)

Ratio of constant terms =\(\frac{4}{12} \) =\(\frac{1}{3} \)

∴ Ratio of coefficients of x = ratio of coefficients of y ratio of constant terms

iii. If ratio of coefficients of x = ratio of coefficients of y ≠ ratio of constant terms, then the graphs of the two equations will be parallel to each other.

Condition of consistency in Equations:

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