i x = 2y = 4
∴ 2y = x - 4
∴ y = \(\frac{x-4}{2} \)
x |
0 |
2 |
-2 |
4 |
y |
-2 |
-1 |
-3 |
0 |
(x,y) |
(0,-2) |
(2,-1) |
(-2,-3 |
(4,0) |
2x - 4y = 12
∴ x - 2y = 6 .........[Dividing both sides by 2]
∴ 2y = x - 6
∴ y= \(\frac{y-6}{2} \)
x |
0 |
-2 |
2 |
4 |
y |
-3 |
-4 |
-2 |
-1 |
(x,y) |
(0,-3) |
(-2,-4) |
(2,-2 |
(4,-1) |

ii. Ratio of coefficients of x =\(\frac{1}{2} \)
Ratio of coefficients of y = \(\frac{-2}{-4} \)=\(\frac{1}{2} \)
Ratio of constant terms =\(\frac{4}{12} \) =\(\frac{1}{3} \)
∴ Ratio of coefficients of x = ratio of coefficients of y ratio of constant terms
iii. If ratio of coefficients of x = ratio of coefficients of y ≠ ratio of constant terms, then the graphs of the two equations will be parallel to each other.
Condition of consistency in Equations:
