Question

Calculate the volume of oxygen required for the complete combustion of 8.8 g of propane (C₃H₈). 

(Atomic mass: C = 14, O = 16, H = 1, Molar Volume 22.4 dm³ at stp).

Answer 1

If oxygen required for 50 gm of C₃H₈ = 112 l.

Then oxygen required for 8.8 gm of C₃H₈ = \(\frac{112}{50}\times8.8\)

                                                                    = 19.172 l.