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If a(y + z) = b(z + x) = c(x + y) and out of a, b, c no two of them are equal, then show that, (y - z)/a(b - c) = (z - x)/b(c - a) = (x - y)/c(a - b)

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Here, no two of a, b and c are equal. 

∴ values of (b – c), (c – a) and (a – b) are not zero. 

a(y + z) = b(z + x) = c(x + y) … [Given]

... [from (ii), (iii) and (iv)]

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