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In the adjoining figure, BP ⊥ AC, CQ ⊥ AB, A – P – C, A – Q – B, then prove that ∆APB and ∆AQC are similar.

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1. proff:

2. SAS test for similarity of triangles: 

For a given correspondence, if two pairs of corresponding sides are in the same proportion and the angle between them is congruent, then the two triangles are similar.

In the given figure, if AB/PQ = BC/QR, and ∠B ≅∠Q, then ∆ABC ~ ∆PQR

3. SSS test for similarity of triangles: 

For a given correspondence, if three sides of one triangle are in proportion with the corresponding three sides of the another triangle, then the two triangles are similar.

In the given figure, of AB/PQ = BC = QR = AC/PR, then ∆ABC ~ ∆PQR

Properties of similar triangles: 

1. Reflexivity: ∆ABC ~ ∆ABC 

2. Symmetry : If ∆ABC ~ ∆DEF, then ∆DEF ~ ∆ABC. 

3. Transitivity: If ∆ABC ~ ∆DEF and ∆DEF ~ ∆GHI, then ∆ABC ~ ∆GHI.

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