Question

In the figure, BEST is a rhombus, then the value of y – x is

(a) 40° (b) 50° (c) 20° (d) 10°

Answer 1

(a) 40° 

From the given figure TS ∥ BE and also BS is transversal line.

By the rule of alternate interior angles, ∠EBS = ∠BST = 40^o

Then, ∠y = 90^o … [∵diagonal bisect at 90^o]

Consider triangle TSO,

By the rule of exterior angle property of triangle

∠STO + ∠TSO = ∠SOE

x + 40^o = 90^o

x = 90^o – 40^o

x = 50^o

So, the value of y – x is = 90^o – 40^o = 50^o