Question

Common factor of 17abc, 34ab², 51a²b is

(a) 17abc (b) 17ab (c) 17ac (d) 17a²b²c

Answer 1

(b) 17ab

The given factors can be written in expanded form as,

17abc = 17 × a × b × c

34ab² = 2 × 17 × a × b × b

51a²b = 3 × 17 × a × a × b

So, common factors in the above is 17 × a × b

= 17ab